Question

Help with output program calculation ( Programming C++)

Answer 1

For the first test output, I don't know how to get electricity charges of 154.52

Answer 2

but, how do I get 154.52?

Answer 3

500 * 154.52/500

Answer 4

154.52/500 is the cost per kwh

Answer 5

Oh nvm I didn't read ur 2nd attachment they tell u how to find cost per kwh

Answer 6

Yea, I know that. The numbers are there for me to check my program calculations. I just don't know what calculations I have to do in order to get 154.52

Answer 7

The 2nd attachment tells u

Answer 8

Yea, I multiply 500 to each one, but my numbers aren't correct.

Answer 9

Not like that

Answer 10

So the base line is 75 let's say

Answer 11

U pay a different cost for kwh used more than 75.. then more than 130% of that

Answer 12

And then another for 200% over base line

Answer 13

500 is clearly over 200%of baseline of 75

Answer 14

Okay so u'll pay
For the lowest price for the first 75 kwh then 2nd lowest from 76 to 1.30*75 % then 3rd lowest for 1.30*75+1 to 150.. then 151 to500 the highest price

Answer 15

So do cases here.
First determine which region your value is in by doing

K=Usage /baseline value

If k < =1
....
Elseif k <=1.3
..
Elseif k <=2
..
Elsif k>2
..

Answer 16

Do u get it

Answer 17

So, I would have to do the full program before getting the value of 154.52 for electricity charges?

Answer 18

U know how the cost is calculated right

Answer 19

The cost of 154.52?
No ... it is still not ringing to me.
Could you show it?

Answer 20

I'll give u aneed example

Say u pay 0.25 for understanding and equal to 75 kwh

Then 0.3 for eveything above 75 to 100

So for 100
You pay 0.25*75 +0.3*(100-75)

Answer 21

I'm on my phone I can't check the prices and all those values you have to post it here

Answer 22

That should say under* and equal 75

Answer 23

U there

Answer 24

Yea, I am sitting here looking at the instructions

Answer 25

while reading your messages*

Answer 26

Okay tell me the 4 costs and the base line value post it here

Answer 27

Per kwh

Answer 28

No ur instructions

Answer 29

The 4 costs for under baseline. 130 percent 200 and then over

Answer 30

$ 0.18151 for each KWH over 0 and less than or equal to BASELINE
(const with the value 76.5)

$ 0.21546 for eah KWH over BASELINE and less than or equal to 130% of BASELINE.

$ 0.27389 for each KWH over 130% of BASELINE and less than or equal 200% of BASELINE.

$ 0.34876 for each KWH over 200% BASELINE

Answer 31

Okay so cost for 500 kwh is
0.18151*76.5+0.21546*(1.3*76.5-76.5)+0.27389*(2*76.5-1.3*76.5)+0.34876*(500-2*76.5)

Answer 32

http://wolframalpha.com/input/?i=0.18151*76.5%2B0.21546*%281.3*76.5-76.5%29%2B0.27389*%282*76.5-1.3*76.5%29%2B0.34876*%28500-2*76.5&x=10&y=14

Answer 33

Yea, I'm figuring out what you did with your equation

Answer 34

Ur paying a different amount for each division

Think about the number line

Answer 35

Your equation is starting to make sense, could you draw a number line for me? My head is like a nut at the moment.

Answer 36

0------75-----97.5-----150-------------500
C1 c2 c3 c4


C1 means cost 1 which is 0.18151

Answer 37

I am gonna do the 2nd output to check my understanding.

Answer 38

Did u figure out the kwh consumed parr

Answer 39

it is 500 / 154.52 like you said?

Answer 40

are you talking about the first one or the 2nd?

Answer 41

2 cases
Current meter reading > previous meter reading

Current meter reading < previous meter reading

Answer 42

Yea, I know how to do the programming side. I'm still clueless on how to find the electricity charges before creating the program.
I understand your equation on how to get 154.52

Answer 43

That stuff that says adjusting max Meterm stuff for rolling over

Answer 44

Okay now code the eqn

Answer 45

Okay, I'll try to manage myself from here on. I don't want to hold you here for anymore longer.

Answer 46

Ok I'm going to sleep then cya

Answer 47

THank you for your patience and helping, including your time :)

Answer 48

Ok before I go so u'll u've ur 4 cases in
Let k be the number of kwh consumed
If k <=1
..
Elseif k <=1.3
..
Elseif k <=2*76.5
0.18151*76.5+0.21546*(1.3*76.5-76.5)+0.27389*(k*76.5-1.3*76.5)

ElseIf k > 2*76.5
0.18151*76.5+0.21546*(1.3*76.5-76.5)+0.27389*(2*76.5-1.3*76.5)+0.34876*(k-2*76.5)

Answer 49

The first 2 cases shud say 1*76.5
And 1.3*76.5

Answer 50

Depending on whice division u are in u can eliminate parts from the equation

Answer 51

case 1:
Else if k <= 76.5
0.18151 * k