Question

How can I count the number of appearance of a number within a range?
Ex:
The category that will serve as a guide:
90-100 Excellent
80-89 Very Good
70-79 Good

the output should be...
score 1: 98
score 2: 99
score 3: 89
score 4: 100
score 5: 75
score 6: 80
score 7: 99
score 8: 76
score 9: 78
score 10: 90

Excellent = 5
Very Good = 2
Good = 3

I appreciate your help :)

Answer 1

int counting(int scores) {

if (scores >= 90 & scores <= 100) {

result = 5;
return result;
} else if (scores >= 80 & scores <= 89) {
result = 3;
return result;

} else if (scores >= 70 & scores <= 79) {
result = 3;

return result;
}
return result;

}

Answer 2

Thank you! :)

Answer 3

um... Can I ask you another question?... you see, I'm doing the same program using array, but my program only reads 9 inputs where it should be 10... I've used [10] & [11] but the output is still the same... what is it that I should look into?

Answer 4

can you post ur code so i can check it

Answer 5

remember an array start with index 0

Answer 6

now with that being said since u want 10 it should look something like
for(int i =0; i< arrayname.lengh;i++)

Answer 7

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}}}\)

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