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Mathematics 7 Online
OpenStudy (amenah8):

I have to solve the following system of equations using elimination, substitution, and graphing. 4x+y=13 6x-y=7 I solved using each way, but I got different answers. Is that supposed to happen? Please help!

OpenStudy (kuoministers):

lol. Can you show how you done it? There is no way you can get different answers

OpenStudy (aihberkhan):

You should not be getting different answers. Do you have to solve it EACH way or can you pick one?

OpenStudy (amenah8):

I have to solve it each way. For elimination, I got (2,5), substitution I got (10, -27), and graphing I got No Solution.

OpenStudy (kuoministers):

The elimination way gets the correct answer btw. Just recheck the substitution or post it here

OpenStudy (amenah8):

For substitution, I did this.

OpenStudy (kuoministers):

I see the mistake. Its +4x not -4

OpenStudy (amenah8):

For graphing, I did this. (The one in the left-hand corner.)

OpenStudy (kuoministers):

On your 3rd line of working out

OpenStudy (amenah8):

But the 4x is positive in the original equation.

OpenStudy (kuoministers):

OpenStudy (amenah8):

could you please explain it?

OpenStudy (kuoministers):

You see in red? THe brackets I drew? That is what you forgot to do.

OpenStudy (amenah8):

yes. could you please wait while i solve so that you can check it?

OpenStudy (kuoministers):

ok..

OpenStudy (amenah8):

x=-3

OpenStudy (amenah8):

wait, no x=10

OpenStudy (amenah8):

and y=-27

OpenStudy (kuoministers):

Hmm nope?

OpenStudy (amenah8):

is x =-3?

OpenStudy (kuoministers):

x should be 2

OpenStudy (amenah8):

could you help me understand how to get that?

OpenStudy (kuoministers):

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