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7. Solar-heat installations successfully reduce the utility bill 60% of the time. What is the probability that at least 9 out of 10 solar-heat installations are successful and will reduce the utility bill? a. 0.0464 b. 0.9432 c. 0.0403 d. 0.8429
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@math&ing001
@freckles
@dan815
@campbell_st
So its a binomial probability question so \[P(9 ~out~ of ~10~ Successes) = \left(\begin{matrix}10 \\ 9\end{matrix}\right)(p)^9(q)^{10-9}\] p is the probability of success q is the probability of failure hope it helps
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q = 1 - p right? I should have known this was a binomial distribution.
I am doing the work hold on
that's correct p = 0.6 q = 0.4
I get 0.09473 I don't think that is right
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