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Mathematics 21 Online
OpenStudy (roseliberty):

hey, i need help with this equation, i solved it but im not sure if it's right: 7(4^2x)=28(4^x) 7(4^2)(4^x)=4(4^x) /7 16(4^x)=4(4^x) /4 4(4^x)=(4^x) 4=(4^x)-(4^x) 4=0

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