Question

Check my answer: differentiation.

Answer 1

\[f(x) = \frac{ x^2cosx }{ 1-sinx }\]

Answer 2

f ' (x) = \[\frac{ (1-sinx) \times [x^2(-sinx)+2xcosx] - [ cosxx^2cosx] }{ (1-sinx)^2 }\]

Answer 3

@AravindG

Answer 4

Be my answer verifier :)

Answer 5

Check the sign.

Answer 6

\[.... - [ -cosx * x^2cosx]\]

Answer 7

The quotient rule has a -ve sign on top ,also you have diff of -sin x

Answer 8

Yeah.

Answer 9

It is correct now?

Answer 10

Yes.

Answer 11

Okay, thanks again :D

Answer 12

I'm looking at a sample quiz, so I don't have the answers for them.

Answer 13

Welcome again lol