Question

someone please help me (√2- √−2)(√8 + √-2 )

Answer 1

Have you considered multiplication?

Answer 2

\[\sqrt{-2}*\sqrt{-2}=\iota \sqrt{2}*\iota \sqrt{2}=i^2*\left( \sqrt{2} \right)^2=-\sqrt{2}\]

Answer 3

correction
not \[-\sqrt{2}\]
it is -2

Answer 4

\[\left( \sqrt{2}-\sqrt{-2} \right)\left( \sqrt{8}+\sqrt{-2} \right)=\sqrt{2*8}+\sqrt{2*-2}-\sqrt{-2*8}-2\]
\[=4+2 \iota-4\iota-2=2-2\iota \]