Question

how do you find the vertex of (x+3)^2 -5

Answer 1

\[(x+3)^2-5\]

Answer 2

Welcome to OpenStudy!

Answer 3

Your equation is in the form of:
y = (x -h)^2 - k

where (h,k) is the vertex!

Answer 4

@Katiethenerd can you now find the vertex? :)

Answer 5

-3 and -5?

Answer 6

It should be in the coordinate form of (x,y)

so (-3,-5) would be how you write the vertex :)