Question

Completing the square? or some other way?
2 + x^2 - x^(-2)

Answer 1

\[2+x^2-\frac{1}{x^2}\] is what you have

Answer 2

is it set equal to zero or sommat? this is not an equation, nothing to solve

Answer 3

\[2+e ^{2t}-e ^{-2t}\]

Answer 4

still not an equation, still nothing to solve

Answer 5

really it might be best to post the whole thing

Answer 6

\[\sqrt{2+e ^{2t}-e ^{-2t}}\]

Answer 7

somehow that equates to
\[\sqrt{(e ^{t} + e ^{-t})^2}\]

Answer 8

sure does, multiply out and you will see it right away

Answer 9

how was I suppose to derive that!?

Answer 10

that i cannot answer

Answer 11

waaaaa? but you're the best?
and all you have for this one is trial and error??

Answer 12

once you see it it is totally clear

Answer 13

meh

Answer 14

thanks tho

Answer 15

\[(\frac{1}{x}+x)^2=\frac{1}{x^2}+2\times x\times \frac{1}{x}+x^2\]