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Mathematics 21 Online
zarkam21 (zarkam21):

Helpppppppppppp will medal

zarkam21 (zarkam21):

OpenStudy (kanwal32):

take the two triangles and apply pythagores with one base x and other 20-x

zarkam21 (zarkam21):

Okay umm is the answer b

OpenStudy (kanwal32):

the answer is not root 10

OpenStudy (kanwal32):

is angle a 90 degree

OpenStudy (kanwal32):

angle A

OpenStudy (kanwal32):

@zarkam21

zarkam21 (zarkam21):

@iGreen

OpenStudy (igreen):

You can use the Pythagorean Theorem to find AB. \(\sf a^2 + 15^2 = 20^2\) Can you solve that for 'a'?

OpenStudy (igreen):

@zarkam21

zarkam21 (zarkam21):

Okay I am here

OpenStudy (igreen):

Can you solve that equation for 'a'?

zarkam21 (zarkam21):

Yes I am doing it now

OpenStudy (igreen):

Okay, hold on.

zarkam21 (zarkam21):

IS it the square root of 70

OpenStudy (igreen):

Okay, triangle CAB is congruent to triangle ADB.

OpenStudy (igreen):

Which means CB/AB = AB/DB

OpenStudy (igreen):

And CB is equal to 20.

zarkam21 (zarkam21):

and would AB be 20-x

zarkam21 (zarkam21):

So it would be 20/AB?

OpenStudy (igreen):

Yes..this is confusing..hold on.

zarkam21 (zarkam21):

Okay =)

OpenStudy (igreen):

CD/CA = CA/CB

OpenStudy (igreen):

Plug in what we know. CD = x CA = 15 CB = 20

OpenStudy (igreen):

Then solve for 'x'

OpenStudy (igreen):

Can you do that @zarkam21

OpenStudy (igreen):

\(\sf \dfrac{x}{15} = \dfrac{15}{20}\)

OpenStudy (igreen):

Just solve that for 'x' and you have your answer.

zarkam21 (zarkam21):

Is it 11.25

OpenStudy (igreen):

Yes, which is equivalent to 45/4.

zarkam21 (zarkam21):

Okay thank ya =)

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