Mathematics
21 Online
zarkam21 (zarkam21):
Helpppppppppppp will medal
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zarkam21 (zarkam21):
OpenStudy (kanwal32):
take the two triangles and apply pythagores
with one base x and other 20-x
zarkam21 (zarkam21):
Okay umm is the answer b
OpenStudy (kanwal32):
the answer is not root 10
OpenStudy (kanwal32):
is angle a 90 degree
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OpenStudy (kanwal32):
angle A
OpenStudy (kanwal32):
@zarkam21
zarkam21 (zarkam21):
@iGreen
OpenStudy (igreen):
You can use the Pythagorean Theorem to find AB.
\(\sf a^2 + 15^2 = 20^2\)
Can you solve that for 'a'?
OpenStudy (igreen):
@zarkam21
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zarkam21 (zarkam21):
Okay I am here
OpenStudy (igreen):
Can you solve that equation for 'a'?
zarkam21 (zarkam21):
Yes I am doing it now
OpenStudy (igreen):
Okay, hold on.
zarkam21 (zarkam21):
IS it the square root of 70
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OpenStudy (igreen):
Okay, triangle CAB is congruent to triangle ADB.
OpenStudy (igreen):
Which means
CB/AB = AB/DB
OpenStudy (igreen):
And CB is equal to 20.
zarkam21 (zarkam21):
and would AB be 20-x
zarkam21 (zarkam21):
So it would be 20/AB?
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OpenStudy (igreen):
Yes..this is confusing..hold on.
zarkam21 (zarkam21):
Okay =)
OpenStudy (igreen):
CD/CA = CA/CB
OpenStudy (igreen):
Plug in what we know.
CD = x
CA = 15
CB = 20
OpenStudy (igreen):
Then solve for 'x'
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OpenStudy (igreen):
Can you do that @zarkam21
OpenStudy (igreen):
\(\sf \dfrac{x}{15} = \dfrac{15}{20}\)
OpenStudy (igreen):
Just solve that for 'x' and you have your answer.
zarkam21 (zarkam21):
Is it 11.25
OpenStudy (igreen):
Yes, which is equivalent to 45/4.
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zarkam21 (zarkam21):
Okay thank ya =)