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\[x^{3} - 1 \ is \ cubic \ polynomial, \ \because \ \it \ is\ only \ one \ which \ has \ power \ 3\]
\[3-4i \ will \ be \ another \ solution why, x = \frac{ -b \pm \sqrt{b^{2} - 4ac} }{ 2a }, \ so \ one\ is \ 3 + 4i \ ans \ another \ is 3 - 4i\]
\[x = 3 \pm 4i , \ so \ one \ is \ 3 + 4i \ and \ another \ is \ 3- 4i\]
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p(x) = (x + 5)(x + 2)x, because it's intersecting x - axis at -5, -2, 0
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thanks !
its my first day, nice site.
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