Check please?
Solve for X, leave in simplest radical form, below I posted my answer and the question
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OpenStudy (bookworm14):
OpenStudy (astrophysics):
Pythagorean theorem\[a^2+b^2=c^2\]
OpenStudy (bookworm14):
that is what I used :)
OpenStudy (mathmale):
When you've supposedly solved an equation, you can check your work by substituting your answer back into the original equation. If the equation is then true, your solution is correct.
OpenStudy (aravindg):
Looks good :)
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OpenStudy (bookworm14):
I substituted my answer and it came out correctly, that means I for sure have this right? It has been a while since I have done these
OpenStudy (mathmale):
Find the square of 2Sqrt(22).
Find the square of 9.
Add these squares together.
Find the square root of this sum.
If your result is 13, your solution 2Sqrt(22) is correct.
OpenStudy (mathmale):
Delete what?
OpenStudy (bookworm14):
Thank you everyone!! :D \(\color{purple}{\Huge\ddot\smile\heartsuit}\)