A concession stand sells hamburgers (h) for $2 and hotdogs (d) for $1. On Friday night they sold a total of 300 hamburgers and hotdogs and made $420. How many of each did they sell?

Which system of equations matches the situation?
A) http://www.usatestprep.com/modules/gallery/file.php?id=12736
B) http://www.usatestprep.com/modules/gallery/file.php?id=12737
C) http://www.usatestprep.com/modules/gallery/file.php?id=12738
D) http://www.usatestprep.com/modules/gallery/file.php?id=12739

Question

A concession stand sells hamburgers (h) for $2 and hotdogs (d) for $1. On Friday night they sold a total of 300 hamburgers and hotdogs and made $420. How many of each did they sell?

Which system of equations matches the situation?
A) http://www.usatestprep.com/modules/gallery/file.php?id=12736	 	
B) http://www.usatestprep.com/modules/gallery/file.php?id=12737	 	
C) http://www.usatestprep.com/modules/gallery/file.php?id=12738	 	
D) http://www.usatestprep.com/modules/gallery/file.php?id=12739

anonymous · Answer

what do you think it is?

retireed · Answer

2h + d = 420
  h + d = 300    multiply -1 and add to the top equation

  h = 420 - 300     d = 300 - (420 - 300)

retireed · Answer

2h + d = 420 
  h + d = 300 or just subtract from the top equation

   h = 420 - 300      d = 300 - (420 - 300)