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Word problem.
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@Directrix
Crank out: change in y over change in x. Average rate of change = [d(10) - d(1)] / [10 - 1) d(t) = 10 t^2 What is d(10) What is d(1) We need those values for the formula. @shaleiah
Post what you get, okay?
8.9?
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What did you get for d(10) = 10 * 10^2 = ?
1000
>1000 Correct And, for d(1) = 10 * 1^2, what did you get?
10
Correct. (1000 - 10 ) = ? (10 - 1) = ?
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990 9
Correct. Average rate of change = [d(10) - d(1)] / [10 - 1) = 990/9 = ?
110
Correct.
thank you so much!!
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