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Mathematics 15 Online
OpenStudy (shaleiah):

Word problem.

OpenStudy (shaleiah):

OpenStudy (shaleiah):

@Directrix

Directrix (directrix):

Crank out: change in y over change in x. Average rate of change = [d(10) - d(1)] / [10 - 1) d(t) = 10 t^2 What is d(10) What is d(1) We need those values for the formula. @shaleiah

Directrix (directrix):

Post what you get, okay?

OpenStudy (shaleiah):

8.9?

Directrix (directrix):

What did you get for d(10) = 10 * 10^2 = ?

OpenStudy (shaleiah):

1000

Directrix (directrix):

>1000 Correct And, for d(1) = 10 * 1^2, what did you get?

OpenStudy (shaleiah):

10

Directrix (directrix):

Correct. (1000 - 10 ) = ? (10 - 1) = ?

OpenStudy (shaleiah):

990 9

Directrix (directrix):

Correct. Average rate of change = [d(10) - d(1)] / [10 - 1) = 990/9 = ?

OpenStudy (shaleiah):

110

Directrix (directrix):

Correct.

OpenStudy (shaleiah):

thank you so much!!

Directrix (directrix):

You are welcome.

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