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Solve the following initial value problem: y′′ + 8y = δ(t −1), y(0)=3, y'(0)=4
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we just need to solve y′′ + 8y=0 for two cases: t<1 and t>1 by figuring out the correct initial conditions for each case
we can expect y to be continuous and y' to have a jump at t=1
so I just ignore the δ(t −1 until I'm plugging in the initial conditions?
yup
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