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If a1,a2,.....,an are in H.P then a1a2+a2a3+..+a n-1 a n =?
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@ParthKohli
well, remember telescopic sums?
(a1-an )/d then ?
\[a_n = a_1 + (n-1)d\]Just solve for \(d\) in the above.
so it is 1-n ?
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no... its not that d ...
hey this is in H.P!
anyway i got the idea.....
yeah, true.
Thanks
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no problem :)
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