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The tangent line to y=f(x) at (3,10) passes through the point (8,−1). Compute the following. a.) f(3)= b.) f′(3)=
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what is f(3)? its the value of y at x=3
from the question, you can see that at x=3, y is 10.
@physo ok that makes sense
use the same logic to do (b)
i don't get how unless its the same answer
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first derivative is the gradient of the tangent at that specific point and gradient = (y2-y1)/(x2-x1)
where (x1,y1) and (x2,y2) are any 2 points on the tangent line
slope= 11/-5
perfect i got it
good job!
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