Question

Log. functions derivative. Is this correct?

Answer 1

\[f(x)=\ln(\sin^2x)\]

Answer 2

\[f'(x) = \frac{ 1 }{ \sin^2x }\times 2cosxsinx\]
=\[\frac{ 2cosxsinx }{ \sin^2x }\]

Answer 3

@zepdrix

Answer 4

Zep, can you check this for me?

Answer 5

This is an even problem in the book, so can't check the answer :(

Answer 6

Looks good so far :o

Answer 7

okay thanks! :D

Answer 8

Cancel out a sine as a final step maybe, ya? :)

Answer 9

Can I write it as 2cotx?

Answer 10

Good good good.\[\large\rm =2\frac{\cos x}{\sin x}\quad=2\cot x\]

Answer 11

okay. cool cool . thanks :)