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In a ∆PQR is 3sinP+4cosQ=6 and 4sinQ+3cosP=1 then the angle R is equal to.... I m getting ans 5π/6 n π/6 Bt the ans is only one... How??
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@parthkohli pls...help
@hartnn @ganeshie8 pls...help me
are you supposed to bring in a form Rsin/cos( x +theta)
No, we r required to find a solution of the two equations which gives us the value for P n Q ....n then find the value of R
Well, i get the final solution as Sin(P+Q)=1/2 this can be d case when P+Q=π/6 or 5π/6
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So i m cuming up with value of R as π/6 or 5π/6 Bt the ans is only one out of d two....
for convenience: p=alpha ,q=beta. suppose alpha+beta=p/6|dw:1455536070999:dw|
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