A block is kept on the floor of an elevator at rest. the elevator starts descending with an acceleration of 12 m/s^2. Find the displacement of the block during the first 0.2 sec after the start. take g=10

Question

jiteshmeghwal9 · Answer

@Vincent-Lyon.Fr sir

vincent-lyon.fr · Answer

Do you mean 1.2 m/s² ?

jiteshmeghwal9 · Answer

no 12 m/s^2

vincent-lyon.fr · Answer

It means the elevator is going faster than free fall. So the object would simply fall under gravity.

jiteshmeghwal9 · Answer

so $$s=\frac{1}{2}g (0.2)^2$$$$s=5 \times 0.04=0.2m$$

jiteshmeghwal9 · Answer

If the elevator had descended with an acceleration of 8 m/s^2. then wht will be the answer ??

vincent-lyon.fr · Answer

Correct.
If the elevator has 8m/s², the body stays in contact with it and will go down with this acceleration.

jiteshmeghwal9 · Answer

thanx A lot sir :)