Geometry
8 Online
OpenStudy (maleena_1):
What is the value of? a right triangle a 30 degree angle and a leg measuring 7(square root)3
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OpenStudy (raffle_snaffle):
okay so draw the triangle.
OpenStudy (maleena_1):
it is drawn
OpenStudy (raffle_snaffle):
where I don't see it
OpenStudy (raffle_snaffle):
Draw the triangle please.
OpenStudy (maleena_1):
|dw:1455772267822:dw|
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OpenStudy (raffle_snaffle):
since we know the 30* angle which one would you use cos(theta), sin(theta), or tan(theta)?
OpenStudy (maleena_1):
I have no clue
OpenStudy (raffle_snaffle):
sin(theta) = opposite/hypotenuse
OpenStudy (raffle_snaffle):
Does that ring a bell?=)
OpenStudy (raffle_snaffle):
what is cos(theta) = ?
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OpenStudy (maleena_1):
cos(theta) = b / c
OpenStudy (raffle_snaffle):
cos(theta) = adjacent/hypotenuse
OpenStudy (raffle_snaffle):
yes if you are saying b = adjacent and c = hypotenuse
OpenStudy (raffle_snaffle):
which side is the hypotenuse?
OpenStudy (maleena_1):
across of the right angle
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OpenStudy (raffle_snaffle):
yes
OpenStudy (maleena_1):
ok
OpenStudy (raffle_snaffle):
so show me the equation with the given side and angle?
OpenStudy (raffle_snaffle):
You would use cos(theta) = adjacent/hypotenuse
OpenStudy (maleena_1):
I am confused
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OpenStudy (raffle_snaffle):
|dw:1455772867260:dw|
OpenStudy (raffle_snaffle):
cos(theta) = adjacent/hypotenuse. You want to solve for w = hypotenuse
OpenStudy (dayakar):
|dw:1455773211000:dw|
OpenStudy (dayakar):
\[C0S 30 = \frac{ AB }{ AC }\]
\[\frac{ \sqrt{3} }{ 2 }= \frac{ 7\sqrt{3} }{ AC }\]
CAN u find AC