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Geometry 5 Online
OpenStudy (maleena_1):

What is the value of? a right triangle a 30 degree angle and a leg measuring 7(square root)3

OpenStudy (raffle_snaffle):

okay so draw the triangle.

OpenStudy (maleena_1):

it is drawn

OpenStudy (raffle_snaffle):

where I don't see it

OpenStudy (raffle_snaffle):

Draw the triangle please.

OpenStudy (maleena_1):

|dw:1455772267822:dw|

OpenStudy (raffle_snaffle):

since we know the 30* angle which one would you use cos(theta), sin(theta), or tan(theta)?

OpenStudy (maleena_1):

I have no clue

OpenStudy (raffle_snaffle):

sin(theta) = opposite/hypotenuse

OpenStudy (raffle_snaffle):

Does that ring a bell?=)

OpenStudy (raffle_snaffle):

what is cos(theta) = ?

OpenStudy (maleena_1):

cos(theta) = b / c

OpenStudy (raffle_snaffle):

cos(theta) = adjacent/hypotenuse

OpenStudy (raffle_snaffle):

yes if you are saying b = adjacent and c = hypotenuse

OpenStudy (raffle_snaffle):

which side is the hypotenuse?

OpenStudy (maleena_1):

across of the right angle

OpenStudy (raffle_snaffle):

yes

OpenStudy (maleena_1):

ok

OpenStudy (raffle_snaffle):

so show me the equation with the given side and angle?

OpenStudy (raffle_snaffle):

You would use cos(theta) = adjacent/hypotenuse

OpenStudy (maleena_1):

I am confused

OpenStudy (raffle_snaffle):

|dw:1455772867260:dw|

OpenStudy (raffle_snaffle):

cos(theta) = adjacent/hypotenuse. You want to solve for w = hypotenuse

OpenStudy (dayakar):

|dw:1455773211000:dw|

OpenStudy (dayakar):

\[C0S 30 = \frac{ AB }{ AC }\] \[\frac{ \sqrt{3} }{ 2 }= \frac{ 7\sqrt{3} }{ AC }\] CAN u find AC

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