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suppose you have natural number n>1,if n is even then you divide it by 2 (n/2) if it is odd then you myltiply it by 3 and add 1 so(3n+1 ) you continue this process until you reach 1.prove that in any case you can reach 1
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hoe 3n+1? shouldn't it be 3n+3 @sparrow2
no 3n+1
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