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Please help me with factoring. I don't know how to do this type of problem, it's not a normal trinomial. 3x^2 y -27y^3
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take 3y common
You mean take out the common factor?
x^2 - 9y^2 Like this? @FaiqRaees
3y (x^2 - 9y^2 )
Is there any other step?
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yes very good
Now \[\large\rm a^2-b^2=(a+b)(a-b)\]
oh right, so (x+9y) (x-9y)
shouldn't the 9 be also get rooted???
no 3y
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Yes that
than correct
Thank you
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