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What are the solutions of the system? Y = X + 5 Y = X^2 - X + 2 A.) (3,14) and (-1, 0) B.) (3, 8) and (-1, 4) C.) (3, 8) and (-1, 0) D.) (-3, 2) and (1, 6)
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y= x+5 -------(1) y = x^2 -x +2------(2) in (1) and (2) left hand sides are equal then right hand sides are equal x^2 -x +2 = x+5
I'm sorry, I'm still confused.
do we have two equations is it clear
Yes.
|dw:1455900970071:dw|
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circled are equal then underlined are equal
Ok.
x^2 -x +2 = x+5 [ add both sides -x-5]
|dw:1455901281445:dw|
x^2+1x-3x-3 =0 [splitting middle term]
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r u following
Yes.
x(x+1)-3(x+1)=0[ taking common] (x+1)(x-3)=0 therefore x+1= 0 or x-3 =0 now find x values
1 and -3?
NO x= -1 or x= 3
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