Question

how do i evaluate this integral?

Answer 1

tried plugging in u = ln x ?

Answer 2

How do i know what to use as u?
I'm sorry, I havent had calc in 2 years..i don't remember how to do any of this.

Answer 3

when we find the derivative of a function in the question itself,
we try taking that as 'u'

i found the derivative of ln x in the function \(\dfrac{(\ln x)^2}{x}dx\) itself :)

Answer 4

\[u=lnx , \frac{ du }{ dx }= \frac{ 1 }{ x }, du = \frac{ 1 }{ x }dx\]

Answer 5

yes, correct
go on