Question

help?

Answer 1

\(\bf \cfrac{(x+3)}{x^2-2x}\cdot \cfrac{(x-2)^2}{x^2-9}\)

take common factor to the first denominator
and
do a difference of square expansion on the second denominator
see what yoiu end up with

Answer 2

man idk

Answer 3

hold on

Answer 4

is it d

Answer 5

or c

Answer 6

i think c

Answer 7

wait no

Answer 8

well. what do you get for those denominators anyway?

Answer 9

a negative?

Answer 10

wait no b because x(x-3)

Answer 11

\(\bf x^2-2x\impliedby \textit{common factor}\\
x^2-9\implies x^2-3^2\impliedby \textit{difference of squares}\)

Answer 12

b?

Answer 13

ur not making sense sorry