Question

select all that apply
sec2x=
a)1/2sin^2 x-1
b)1/1-2sin^2 x
c)1/sin^2 x-cos^2 x
d) cos^2 x-sin^2 x

Answer 1

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Hint: \(\bf\Large sec(x) =\frac{1}{cos(x)}\)

So:

\(\bf\Large sec(2x) =\frac{1}{cos(2x)}\)

Do you know the identities for cos(2x) ?

Answer 2

@o_mor11

Are you there?