Question

partial derivative of t [A sin (B*t -C*x)]
can some one check my answer ?
A*cos(B*t-C*x)*(B)
is this it or this
A*cos(B*t-C*x)*(B-C*x)

Answer 1

\(\dfrac{\partial}{\partial t}(Asin(Bt-Cx)=AB cos(Bt-Cx)\)

Answer 2

K, thanks!