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Two point charges are fixed on the y axis: a negative point charge q1 = -26 μC at y1 = +0.18 m and a positive point charge q2 at y2 = +0.31 m. A third point charge q = +8.2 μC is fixed at the origin. The net electrostatic force exerted on the charge q by the other two charges has a magnitude of 31 N and points in the +y direction. Determine the magnitude of q2.
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U hv to use the equation F=(1/4*pi*efcylon not)(q1*q2/r^2
And F=F1+F2
U know force between 2 positive charges is positive
Foce between a positive n a negative charge is negative
Here F=31N
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U can draw it for solving
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