Question

Differentiate

Answer 1

\[y=e^{\tan \pi t}\]

Answer 2

your attempt?
needs chain rule

Answer 3

Let u = tan pi t
y = e^u
\[y' = \frac{ d }{ du }(e^u) \times \frac{ d }{ dt }(\tan \pi t)\]
\[y' = e^u \times \sec^2 \pi t \times \pi\]
\[y ' = e^{\tan \pi t}\pi \sec^2 \pi t\]

Answer 4

@hartnn is that correct?

Answer 5

hi, sorry for late reply!
and yes, thats correct :)