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Mathematics 5 Online
OpenStudy (anonymous):

PLEASE HELP! Subtract 42 base five-13 base five

OpenStudy (anonymous):

For instance, to represent 24 in base 10 using sticks, you could use two groups of ten and 4 as shown below 28 in base 10 However, to represent the same number in base 5, you make groups of 5 28 in base 5 Notice that you have 4 groups of five and 4. You write 44five or 445 Thus, 2410 = 445 Be very careful when you read 44five! You don't read it as fourty four because this is how you read four tens and four in base 10. We are not in base 10 anymore 445 is read four four base 5 In like manner, if you group 17 in groups of five, you can get three groups of 5 and 2 17 in base 5 You write 1710 = 325 and 325 is read three two base 5 Look at the following pattern: 1910 = 345 1810 = 335 1710 = 325 1610 = 315 1510 = ? What do you think 15 is in base 5? Yes, 1510 = 305 = ? This is important. It is not 3 just because we have three fives in 15 In fact, what it means is three fives in the second place value and zero number in the first place value The first ten base 5 numerals are shown below: 15 25 35 45 105 115 125 135 145 205 Notice that the first four numbers have the same representation in base 10 and in base 5 The second difference between base five and base ten is that in base ten, we use the 10 digits 0, 1, 2, 3 , 4 , 5, 6, 7, 8, and 9 In base 10, when you have 10 tens, you replace it by one hundred and starting from the right one hundred is in the third position In general, place values are power of 10: 100 = 1, 101 = 10, 102 = 100, 103 = 1000, etc. representing first, second, third place etc repectively. On the other hand, In base 5, we use only 5 digits 0, 1, 2, 3 , and 4 In base five, when you have 5 fives, you replace it by one twenty five and starting from the right twenty five is in the third position In this case, place values are power of 5: 50 = 1, 51 = 5, 52 = 25, 53 = 125, etc representing first, second, third place etc.respectively.. Having said that, what is 57 in base 5 Group 57 in groups of 25 and 5 57 has 2 groups of 25, 1 group of 5 and 2, so 5710 = 2125

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