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OpenStudy (anonymous):
Please help! :) 49^ 5x+2 = (1/7)^ 11-x
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umerlodhi (umerlodhi):
1 sec
OpenStudy (anonymous):
\[49=7^2\\ \frac{1}{7}=7^{-1}\] is a start
OpenStudy (anonymous):
Yea i thought of 49= 7^2 but idk where to put the 2 in 5x+2
OpenStudy (triciaal):
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