Question

What are the holes of g(x) = (x^2+3x-4)/(x^2+9x+20)?

Answer 1

begin by factoring numerator and denominator

look at the factors that you can cancel from top and bottom to find holes

Answer 2

((x + 4)(x + 1))/((x + 5)(x + 4))

So x + 4 cancels out. Is that the only hole?

Answer 3

the top is actually (x+4)(x-1)

but x+4=0 gives us the hole