Medal for best answer!!!!!! MThe distance traveled, in meters, of a coin dropped from a tall building is modeled by the equation d(t) = 4.9t2 where d equals the distance traveled at time t seconds and t equals the time in seconds. What does the average rate of change of d(t) from t = 3 to t = 6 represent? (2 points) The coin travels an average distance of 44.1 meters from 3 seconds to 6 seconds. The coin falls down with an average speed of 14.7 meters per second from 3 seconds to 6 seconds. The coin falls down with an average speed of 44.1 meters per second from 3 seconds to 6 seconds.
The coin travels an average distance of 14.7 meters from 3 seconds to 6 seconds.
@rebeccaxhawaii
@whpalmer4
@foolofatook
I think it is either the B or D
\[\large{ \text{Average}=\cfrac{1}{6-3}\int\limits_3^6{4.9t^2dt}=\cfrac{1}{3}\times\cfrac{4.9t^3}{3}|^6_3\\ =\cfrac{4.9}{9}\times\left(6^3-3^3\right)\ }\] The average rate of change is the average velocity: \[\large{ \text{Average Velocity }=\cfrac{1}{6-3}\int\limits_3^6{\cfrac{d}{dt}4.9t^2dt}\\= \cfrac{1}{3}4.9t^2|_3^6=4.9\times\cfrac{6^2-3^2}{3}=44.1~m/s }\] So it travels at a speed of 44.1 m/s from 3 seconds to 6 seconds
Okay but it says to find average rate or change so 3-6=3
44.1 divided by 3 =14.7
Ok...
I just dont get from which 2 I should pick B Or D
x/t is speed. So the rate of change will be related to speed. At t=3; the coin is falling at 29.4m/s and at t-6; the coin is falling at 58.8m/s. If you take these and add them together, then divide by 2, you'll get rate per 3 seconds. Divide by 3 and you get 14.7m/s.
That's what you where saying correct?
Yes
Now what answer choice should i pick B or D?
B :)
Are you sure is there any difference between 2?
Yes, one says travels and the other says falls
Okay can you help me with one more?
Yes, but please close this question and open a new one!
Okay ill tag you
@Ineedhelplz
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