Question

I need help with Logarithms... I freaking hate them! ;-; someone help please?

Answer 1

https://www.khanacademy.org/math/algebra2/exponential-and-logarithmic-functions/introduction-to-logarithms/v/logarithms

Answer 2

uhm... tried that place.

Answer 3

it was the first place I looked.

Answer 4

but thanks anyways @Pandabear500

Answer 5

anyone else willing to help?

Answer 6

do you have a specific question you need help with?

Answer 7

no more like I wanna understand them in general

Answer 8

I am freaking crying over these cause of my school work and I want to learn ways to be able to solve them without going through a ton of freaking work

Answer 9

@hartnn you there dude? or are you looking up something?

Answer 10

There are just a bunch of formulas you need to practice while studying Logarithm..

Also, if Khan Academy doesn't help, I am not sure what will!
maybe mathisfun.com ?

Answer 11

oh. thanks anyways.

Answer 12

It's difficult to help when you don't have a specific issue.

"Logarithms" is a large topic and I can't write the book on them here.

Have you studied the rules of 'exponents' prior to this - because logs are based on those rules

(e.g. a^m * a^n = a ^ m+n) etc.??

Answer 13

I know the formulas. its executing them that I have a problem with

Answer 14

mostly using logs is just addition or subtraction , sometimes multiplication and division.

But the whole point of logs is to use addition of exponents etc. instead of multiplication...

Do you understand that adding logs is adding exponents which is ht same as multiplying?

Answer 15

or subtracting right?

Answer 16

subtracting logs is subtracting exponents which is the same as dividing...

Answer 17

ah

Answer 18

but could you give me an example so I can take notes?

Answer 19

I think his computer either froze or he got disconected

Answer 20

I can - but htere are plenty of better texts and sites available with examples. Nobody can implant the knowledge in oyu without 'freakin' work.

Here is a very simple example:

100 * 1000 = x

10^2 * 10^3 = x

take logs:

log 10^2 + log 10^3 = log x

2 + 3 = log x

5 = log x

10^5 = x

100,000 = x

Answer 21

ah alright and I deserved that ^^;

Answer 22

thanks! that actually helped a lot. I have no idea what I was so worried with.

Answer 23

np