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What value is not in the domain. (x-2)/(x+3)
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Critical values: the denominator can't equal zero because anything divided by zero is undefined.\[\frac{x-2}{x+3},x+3\ne 0\rightarrow x\ne -3\]
hint: \(\bf \cfrac{x-2}{x-3}\qquad {\color{brown}{ x=3}}\implies \cfrac{x-2}{{\color{brown}{ 3}}-3}\implies \cfrac{x-2}{0}\impliedby undefined \)
So is the answer -3?
yes
Yes :-)
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Since division by 0 has no meaning in the set of real numbers.
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