Question

Please Help!!

Answer 1

first step : subtract 22 on both sides

Answer 2

i did that but im not sure where to go from there

Answer 3

so now u got
\[64^{-3x-3}\times64 = 16\]
u remember
\[a^x \times a^y = a^{x+y}\]

Answer 4

so it is
\[64^{-3x-2} = 16\]
now u see 16 = 2^4
and 64 = 2^6

Answer 5

thank you @rishavraj i got the answer

Answer 6

u welcome :))