What is the length of segment AB? 5 units 6 units 8 units 10 units
Any image?
I think its 5, tell me what you think it is
hmm what are the endpoints for AB anyway?
(6,2) and (0,10)
well, ok then \(\bf \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &A({\color{red}{ 6}}\quad ,&{\color{blue}{ 2}})\quad % (c,d) &B({\color{red}{ 0}}\quad ,&{\color{blue}{ 10}}) \end{array}\qquad % distance value d = \sqrt{({\color{red}{ x_2}}-{\color{red}{ x_1}})^2 + ({\color{blue}{ y_2}}-{\color{blue}{ y_1}})^2}\)
I thought you use the formula\[a^{2} + b^{2} = c^{2}\]
yes, the pythagorean theorem is pretty much that, to find the distance between two spots in the case of a rignt triangle, to find hypotenuse
did you get it?
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