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The work of a student to solve the equation 3(3y − 8) = 10 + 3y is shown below: Step 1: 3(3y − 8) = 10 + 3y Step 2: 6y − 5 = 10 + 3y Step 3: 3y − 5 = 10 Step 4: 3y = 15 Step 5: y = 5 In which step did the student first make an error and what is the correct step? Step 2: 9y − 24 = 10 + 3y Step 2: 6y + 11 = 10 + 4y Step 3: 6y − 8 = 3(6 + y) Step 3: 3(3y − 8) = 7 + y
Step 1: 3(3y − 8) = 10 + 3y is writing the problem step 2 is to distribute the 3 what do you get?
i confused with the question
im not good at math
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