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Find all solutions in the interval [0, 2π). (sin x)(cos x) = 0
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such eqution, is equivalent to these equations: \[\begin{gathered} \sin x = 0 \hfill \\ \cos x = 0 \hfill \\ \end{gathered} \] please solve them
cos = 0 at 90 degrees or pi/2 radians
and sin at 180 degrees
more precisely, we have: \[\cos x = 0\] when: \[x = \frac{\pi }{2},\quad x = \frac{{3\pi }}{2}\]
Hint: theres another value when cos = 0
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- what Michelle siad
|dw:1456601783900:dw|
and: |dw:1456601864567:dw|
please keep in mind that the coordinates of a generic point \(P\), on the trigonometric circle, are: \[P = \left( {\cos \theta ,\sin \theta } \right)\] |dw:1456602006270:dw|
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