Question

From what height above the surface of the earth should an object be dropped to initially experience an acceleration of 0.54g?

Answer 1

I think that we can apply this formula:
\[\Large g' = K\frac{M}{{{{\left( {R + h} \right)}^2}}}\]
where \(g'=0.54\times g\) \(M\) is the mass of earth, and \(R\) is the radius of earth.
\(K\) is the constant of Newton, and \(h\) is the requested height

Answer 2

Ahhh that formula. Thank you.