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Exponential Functions. Need help finding x. Equation posted below.
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\[25(2)^x=325\]
I've reduced that to \[2^x=13\] and that to \[\sqrt[x]{13}=2\]
This needs to be a real number answer rounded to two decimal places. Solve for x.
take logs of both sides ln 2^x = ln 13 then use on of the laws of logs x ln 2 = ln 13
@hhopke If you will perform the operation (last line) in the post above, you will get what you need.
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Or to make it simple, x = ln13/ln2
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