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Hi Guru's, I want to find the coordinates of X in the following question: In a Diagram, the points A and C lie on the X- and Y- axes respectively and the equation of AC is 2y+x=16. The point B has coordinates (2,2). The perpendicular from B to AC meets AC at the point X. Also, i have to find the coordinates of D, such that the Quadrilateral ABCD has AC as line of symmetry. Looking forward for the solution with explaination. Thank you in advance for your help.
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|dw:1456743464106:dw|
Area of triangle = \[\frac{1}{2}\left| x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2) \right|\]
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