Question

integrate by parts..what did i do wrong?

Answer 1

\[\int\limits_{1}^{2} \frac{ 8\ln(x) }{ x^2 }dx\]
\[u = \ln(x) , du = \frac{ 1 }{ x }dx , dv = \frac{ 8 }{ x^2 }dx , v = \frac{ -8 }{ x }\]

Answer 2

are those the correct substitutions?

Answer 3

nevermind, i got the answer.