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Inverse function of 1 over 3x-2? I'm stumped on how to isolate the x if it's in the denominator.
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\[f(x)=1/(3x-2)\]
1. Replace f(x) with y. 2. Interchange x and y. 3. Sove the resulting equation for y. 4. Replace that y by \[f ^{-1}(x)=\]
3. Solve
Solved already :P Thx anyways
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