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ill try
\[4^x*(1/2)^{3x+2}=8*(2^x)^2\]
Ty :D
So far i got this \[(2^2)^x*(2^{-1})^{3-2x}=(2^3)*(2^x)^2\]
Never mind i figured out what I did wrong :P You add the exponents if they're the same base not multiply silly me lol.
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