Question

Would you do integration by parts to solve this thing

https://www.dropbox.com/s/mxcp1u37p5bf0vq/Screenshot%202016-03-01%2020.36.22.png?dl=0

?

Or is there a simpler way ?

Answer 1

IBP is already a pretty straight forward approach

just separate x^2 = x.x and bish bosh

Answer 2

As an alternative, you could use a trig substitution : \(x = \sqrt{7}\tan u\)

Answer 3

OMG

a lot uglier than i thought initially. ganesh's idea is better than IBP, IMHO.

maybe even try \(x^2 = 7 \sinh^2 u\), though hindsight is 20:20 :-))