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what is the turning point of the graph f(x)=|x+3|-2 A.(-3,-2) B.(-2,-3) C.(-3,2) D.(2,-3)
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what value of "x" would make \(\bf x+3 \) be 0 you think?
i think -3,2
x = -3,2? that'd be a dual value for a variable though
im so confused... i dont know how to do this sorry
@jdoe0001 plz help if you know it
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