Ask
your own question, for FREE!
Mathematics
13 Online
OpenStudy (juan1857):
can anyone pls help:
Solve each equation for principal values of Express solutions in degrees; sin2x-1=0
Join the QuestionCove community and study together with friends!
Sign Up
TheSmartOne (thesmartone):
Hint:
sin 90 degrees = 1
TheSmartOne (thesmartone):
sin2x-1=0
Add 1 to both sides. What do you get?
OpenStudy (juan1857):
sin2x=1 right?
TheSmartOne (thesmartone):
correct
and we know that sin 90 degrees = 1
so that means
sin 2x = sin 90
and removing sin we get:
2x = 90 degrees
what is x = ?
TheSmartOne (thesmartone):
missing steps:
sin2x=1
sin 90 = 1
since they are both equal to 1, we can equate them to each other
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (juan1857):
45
TheSmartOne (thesmartone):
and 45 degrees is your answer :)
Did you understand?
OpenStudy (juan1857):
I understand most of it, but don't understand how sin2x=sin90
TheSmartOne (thesmartone):
well, we know that
sin 2x = 1
and we know that
sin 90 degrees = 1
sin 2x = 1 = sin 90 degrees = 1
sin 2x = sin 90 degrees = 1
sin 2x = sin 90°
OpenStudy (juan1857):
OHH, OK now i get it
THANKS
Join the QuestionCove community and study together with friends!
Sign Up
TheSmartOne (thesmartone):
Anytime! Also, welcome to OpenStudy! :D
OpenStudy (juan1857):
thanks
TheSmartOne (thesmartone):
Anytime! Also, welcome to OpenStudy! :D
TheSmartOne (thesmartone):
Anytime!
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!