Question

PLEASE HELPPP

Answer 1

whats the question

Answer 2

\[\log_{6} 4 \approx 0.774 and \log_{6} 3 \approx 0.613\]

Answer 3

to evaluate

Answer 4

\[\log_{6} 9\]

Answer 5

ummm thats really hard let me see what i can do

Answer 6

do you know this property?
\(\Large \log b^n = n\log b\)

Answer 7

no ):

Answer 8

well, you know now...you can use it!

Answer 9

9 is 3^2, right?

Answer 10

yes

Answer 11

so,
\(\log _6 9 = \log_6 3^2 = 2 \log_6 3 = ...\)

Answer 12

not sure how to do that part

Answer 13

you got what i did?

Answer 14

yes

Answer 15

just dont know how to solve that

Answer 16

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Daisyloveeee
\[\log_{6} 4 \approx 0.774 and \log_{6} 3 \approx 0.613\]
\(\color{#0cbb34}{\text{End of Quote}}\)

you already have the value of \(\log_63\)
just plug that in

Answer 17

so 2 times 0.613?

Answer 18

yes

Answer 19

1.226

Answer 20

thanks :)

Answer 21

\(\huge\checkmark \)
welcome ^_^